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If a person can clearly see an object at 20 feet that can be seen at 60 feet by a person with no refractive error, how is their visual acuity described?

  1. 20/40

  2. 20/60

  3. 20/20

  4. 20/80

The correct answer is: 20/60

In this scenario, visual acuity is assessed based on the ability of a person to see an object at a specified distance compared to what a person with normal vision can see at a greater distance. Visual acuity is expressed as a fraction, where the numerator represents the distance at which the test person can see an object clearly, and the denominator represents the distance at which a person with normal vision (20/20) can see the same object clearly. If the individual can see an object clearly at 20 feet, but a person with normal vision can only see that same object clearly at 60 feet, the comparison indicates that the individual has reduced visual acuity. This is expressed as a fraction of the distance they can see (20 feet) over the distance a person with normal vision can see (60 feet). Hence, the visual acuity for this individual is described as 20/60. This means that while the individual can see clearly at 20 feet, they would need to be much closer to the object than someone with normal vision to see it clearly; normal vision requires a distance of 60 feet. Thus, the person’s ability to see is less than that of someone with 20/20 vision.